4p^2=20+12p

Solution for 4p^2=20+12p equation:

4p^2=20+12p

We move all terms to the left:

4p^2-(20+12p)=0

We add all the numbers together, and all the variables

4p^2-(12p+20)=0

We get rid of parentheses

4p^2-12p-20=0

a = 4; b = -12; c = -20;
Δ = b2-4ac
Δ = -122-4·4·(-20)
Δ = 464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{464}=\sqrt{16*29}=\sqrt{16}*\sqrt{29}=4\sqrt{29}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{29}}{2*4}=\frac{12-4\sqrt{29}}{8}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{29}}{2*4}=\frac{12+4\sqrt{29}}{8}
$